Interaction between Artificial and Naturally Generated Neural
Activity
The
question we want to answer here is ‘What is the effective
rate action potentials are received when an electrical stimulus
is applied to a nerve carrying naturally generated action
potentials?’ To answer this question several assumptions
will be made:
1. The generator acts as a leaky integrator that can be
reset by depolarization before threshold is reached.
2. The stimulus results in action potentials that propagate
in both directions from the site of the stimulus.
3. Collision of and orthodromic traveling action potential
with and an action potential traveling in the antidromic
direction results in the annihilation of both pulses.
PULSE # 1 At t =(x/2)/v the action potential initiated at
the generator and the one initiated at the stimulator collide
at x/2. PULSE # 2 At t = 1/fs a stimulator action potential is initiated
and at Dt later an action potential is initiated at the generator,
where Dt = 1/fg - 1/fs. At the time Dt the stimulator initiated
action potential has moved away from the stimulation site
a distance d= v Dt, where v is the conduction velocity of
the action potential. The collision point for the second
two action potentials is closer to the generator site than
was the site for the first two action potentials. PULSE # 3 At 2Dt the action potentials have traveled a distance
d’ away from the stimulus site before the third action
potential has been initiated at the generator site, where
d’=2v Dt or 2d. The collision site for the third pair
of action potentials is 1/2(x-2d). PULSE #n The collision point for the nth pair of action
potentials is 1/2[x-(n-1)d] = 1/2[x-(n-1)v(1/fg-1/fs)]. When
(n-1)v(1/fg-1/fs)≥x
the stimulator initiated action potential invades the generator
and all succeeding stimulator generated pulses reset the
generator before the generator pulses are initiated. Note
that at the nerve terminal the end organ receives an action
potential for each stimulator initiated pulse and a frequency
that is equal to fs.
PULSE # 2 At a time v(1fs-1/fg) after the second action
potential has been initiated at the generator and action
potential
will
be initiated at the stimulator site
The collision site will be closer to the stimulation site
than x/2. The new collision site will be
v(1/fs-1/fg) + 1/2[x-v(1/fs-1/fg)] = 1/2[x+v(1/fs-1/fg)].
PULSE #n The collision site for the nth pair of
action potentials will be 1/2[x+(n-1)v(1/fs-1/fg)]. However,
when (n-1)v(1/fs-1/fg)>x
a generator initiated action potential will be beyond the
stimulation site and thus escape annihilation by collision.
Up until this each generator initiated action potential
was annihilated by a stimulator initiated action potential
and
for every annihilated generator initiated action potential
a stimulator initiated action potential was sent to the
end organ at a frequency fs. However, when a generator
initiated
action potential escapes annihilation and is transmitted
to the end organ the instantaneous frequency will no longer
be fs but would required to be greater than fs. Since an
action potential is received for every generator initiated
action potential the average frequency for the end organ
received action potentials must be fg, with the lowest
observe frequency being fs.